Codeforcces Solution of 50A- Domino Pilling in C language

Codeforcces Solution of 50A Domino Pilling in C language

Hi friends, In this post I'm gonna give you the solution of the codeforces problem 50A - Domino Pilling.
The problem screenshot is given below:

Code:
/// Bismillahir Rahmanir Rahim /// Author: Razinul Karim /// CSE University of Barishal #include<stdio.h>int main() { int N,M,s; scanf("%d%d",&M,&N); if(M>=1 && N<=16) { s=(M*N)/2; } printf("%d",s); return 0; }

  Happy coding!!!

Codeforces Solution of 158-A Next Round in C Language

Hi friends, In this post I am gonna give you the solution of the codeforces problem: 158A - Next Round.
The problem screenshot is given below:

71A - Way Too Long Words -cfsolv

#include<stdio.h>#include<ctype.h>int main(){ int n,i,m; char x[6000]; scanf("%d",&n); for(i=1;i<=n;i++){ scanf("%s",&x); int l=strlen(x); if(l>10){ printf("%c",x[0]); printf("%d",l-2); printf("%c\n",x[l-1]); } else printf("%s\n",x);} return 0; }

Codeforces Solution of -118A String Task

Codeforces Solution of 118A String Task in C language

Hi friends, In this post I'm gonna give you the solution of the codeforces problem 118A - String Task.
The problem screenshot is given below:

Code:
/// Bismillahir Rahmanir Rahim /// Author: Razinul Karim /// CSE University of Barishal #include<stdio.h> #include<string.h> int main() { int i,l; char s[101]; scanf("%s",s); l=strlen(s); for(i=0; i<l; i++) { if(s[i]!='a' && s[i]!='A' && s[i]!='e' && s[i]!='E' && s[i]!='i' && s[i]!='I' && s[i]!='o' && s[i]!='O' && s[i]!='u' && s[i]!='U' && s[i]!='y' && s[i]!='Y') { if(s[i]<='Z') s[i]+=32; printf(".%c",s[i]); } } printf("\n"); return 0; }

  Happy coding!!!

Codeforces Solutions Of 71A- Way Too Long Words in C Language

Hi friends, In this post I am gonna give you the solution of the codeforces problem: 71A - Way Too Long Words.
The problem screenshot is given below:

71A - Way Too Long Words -cfsolv

#include<stdio.h>#include<ctype.h>int main(){ int n,i,m; char x[6000]; scanf("%d",&n); for(i=1;i<=n;i++){ scanf("%s",&x); int l=strlen(x); if(l>10){ printf("%c",x[0]); printf("%d",l-2); printf("%c\n",x[l-1]); } else printf("%s\n",x);} return 0; }