Codeforces Solution of 112A - Petya and Strings in C

Hi friends, I am going to post the solve of the problem '112A - Petya and Strings' of Codeforces.
The problem screenshot is given below:

Code:
/// OmShantihari /// Author: Sujan Mridha /// CSE, University of Barishal#include<stdio.h>#include<string.h>int main() { int x, i,o,l; x=0; char a[200],b[200]; scanf("%s %s",&a,&b); l=strlen(a); for (i=0;i<l;i++) { o=a[i]-b[i]; if (o!=0 && o!=32 && o!=-32) { if (a[i]<='z' && b[i]<='z' && a[i]>='a' && b[i]>='a') { if (a[i]>b[i]) { x=1; break; } else { x=-1; break; } } if (a[i]<='Z' && b[i]<='Z' && a[i]>='A' && b[i]>='A') { if (a[i]>b[i]) { x=1; break; } else { x=-1; break; } } if (a[i]<='Z' && a[i]>='A' && b[i]<='z' && b[i]>='a') { if (a[i]+32>b[i]) { x=1; break; } else { x=-1; break; } } if (a[i]<='z' && a[i]>='a' && b[i]<='Z' && b[i]>='A') { if (a[i]-32>b[i]) { x=1; break; } else { x=-1; break; } } } } printf("%d\n",x); return 0; }

Codeforces Solutions- 96A Football

Hi friends, In this post I am gonna give you the solution of the codeforces problem: 96A - Football.
The problem screenshot is given below:


/// OmShantihari /// Author: Sujan Mridha /// CSE, University of Barishal #include<stdio.h>#include<string.h>int main() { int i,o,p=0; char n[700]; scanf("%s",&n); o=strlen(n); for (i=0;i<o-6;i++) { if (n[i]=='0' && n[i+1]=='0' && n[i+2]=='0' && n[i+3]=='0' && n[i+4]=='0' && n[i+5]=='0' && n[i+6]=='0') { p=7; break; } if (n[i]=='1' && n[i+1]=='1' && n[i+2]=='1' && n[i+3]=='1' && n[i+4]=='1' && n[i+5]=='1' && n[i+6]=='1') { p=7; break; } } if (p==7) printf("YES\n"); else printf("NO\n"); return 0; }

Solutions Of Codeforces Problem- A Bit++ in C language

Problem screenshot is given Below:

Code:
#include<stdio.h>#include<string.h>int main(){ int i,t,s=0; char x[4]; scanf("%d",&t); for(i=1;i<=t;i++){ scanf("%s",&x); if((strcmp(x,"X++")==0)||(strcmp(x,"++X")==0)){ s=s+1; } else if((strcmp(x,"X--")==0)||(strcmp(x,"--X")==0)){ s=s-1; } s=s; } printf("%d\n",s); return 0; }

Codeforces Problems' Solution (122A - Lucky Division) in C

#include<stdio.h> int main () { int n; scanf("%d", &n); if(((n % 4) == 0) || ((n % 7) == 0) || ((n % 44) == 0) || ((n % 47) == 0) | ((n % 74) == 0) || ((n % 444) == 0) || ((n % 447) == 0) || ((n % 474) == 0) || ((n % 477) == 0)) { printf("YES\n"); } else { printf("NO\n"); } return 0; }